1 package Moose::Meta::TypeConstraint::Role;
7 use Scalar::Util 'blessed';
8 use Moose::Util::TypeConstraints ();
10 use base 'Moose::Meta::TypeConstraint';
12 __PACKAGE__->meta->add_attribute('role' => (
17 my ( $class, %args ) = @_;
19 $args{parent} = Moose::Util::TypeConstraints::find_type_constraint('Object');
21 my $role_name = $args{role};
22 $args{constraint} = sub { Moose::Util::does_role( $_[0], $role_name ) };
24 my $self = $class->_new( \%args );
26 $self->_create_hand_optimized_type_constraint;
27 $self->compile_type_constraint();
32 sub _create_hand_optimized_type_constraint {
34 my $role = $self->role;
35 $self->hand_optimized_type_constraint(
36 sub { Moose::Util::does_role($_[0], $role) }
45 # FIXME find_type_constraint might find a TC named after the role but that isn't really it
46 # I did this anyway since it's a convention that preceded TypeConstraint::Role, and it should DWIM
47 # if anybody thinks this problematic please discuss on IRC.
48 # a possible fix is to add by attr indexing to the type registry to find types of a certain property
49 # regardless of their name
50 Moose::Util::TypeConstraints::find_type_constraint($_)
52 __PACKAGE__->new( role => $_, name => "__ANON__" )
53 } @{ Class::MOP::class_of($self->role)->get_roles },
58 my ( $self, $type_or_name ) = @_;
60 my $other = Moose::Util::TypeConstraints::find_type_constraint($type_or_name);
62 return unless defined $other;
63 return unless $other->isa(__PACKAGE__);
65 return $self->role eq $other->role;
69 my ($self, $type_or_name) = @_;
71 my $type = Moose::Util::TypeConstraints::find_type_constraint($type_or_name);
73 ($self->equals($type) || $self->is_subtype_of($type_or_name));
77 my ($self, $type_or_name_or_role ) = @_;
79 if ( not ref $type_or_name_or_role ) {
81 return 1 if Class::MOP::class_of($self->role)->does_role( $type_or_name_or_role );
84 my $type = Moose::Util::TypeConstraints::find_type_constraint($type_or_name_or_role);
86 return unless defined $type;
88 if ( $type->isa(__PACKAGE__) ) {
89 # if $type_or_name_or_role isn't a role, it might be the TC name of another ::Role type
90 # or it could also just be a type object in this branch
91 return Class::MOP::class_of($self->role)->does_role( $type->role );
93 # the only other thing we are a subtype of is Object
94 $self->SUPER::is_subtype_of($type);
98 sub create_child_type {
99 my ($self, @args) = @_;
100 return Moose::Meta::TypeConstraint->new(@args, parent => $self);
105 # ABSTRACT: Role/TypeConstraint parallel hierarchy
113 This class represents type constraints for a role.
117 C<Moose::Meta::TypeConstraint::Role> is a subclass of
118 L<Moose::Meta::TypeConstraint>.
124 =item B<< Moose::Meta::TypeConstraint::Role->new(%options) >>
126 This creates a new role type constraint based on the given
129 It takes the same options as its parent, with two exceptions. First,
130 it requires an additional option, C<role>, which is name of the
131 constraint's role. Second, it automatically sets the parent to the
134 The constructor also overrides the hand optimized type constraint with
135 one it creates internally.
137 =item B<< $constraint->role >>
139 Returns the role name associated with the constraint.
141 =item B<< $constraint->parents >>
143 Returns all the type's parent types, corresponding to the roles that
146 =item B<< $constraint->is_subtype_of($type_name_or_object) >>
148 If the given type is also a role type, then this checks that the
149 type's role does the other type's role.
151 Otherwise it falls back to the implementation in
152 L<Moose::Meta::TypeConstraint>.
154 =item B<< $constraint->create_child_type(%options) >>
156 This returns a new L<Moose::Meta::TypeConstraint> object with the type
159 Note that it does I<not> return a C<Moose::Meta::TypeConstraint::Role>
166 See L<Moose/BUGS> for details on reporting bugs.