Retire DBIC/SqlMakerTest.pm now that SQLA::Test provides the same function
[dbsrgits/DBIx-Class.git] / t / resultset / as_subselect_rs.t
CommitLineData
e4bb6727 1use strict;
2use warnings;
3
4use Test::More;
5use Test::Exception;
6
7use lib qw(t/lib);
a5a7bb73 8use DBICTest ':DiffSQL';
e4bb6727 9
10my $schema = DBICTest->init_schema();
11
12my $new_rs = $schema->resultset('Artist')->search({
13 'artwork_to_artist.artist_id' => 1
14}, {
15 join => 'artwork_to_artist'
16});
17lives_ok { $new_rs->count } 'regular search works';
18lives_ok { $new_rs->search({ 'artwork_to_artist.artwork_cd_id' => 1})->count }
19 '... and chaining off that using join works';
20lives_ok { $new_rs->search({ 'artwork_to_artist.artwork_cd_id' => 1})->as_subselect_rs->count }
21 '... and chaining off the virtual view works';
22dies_ok { $new_rs->as_subselect_rs->search({'artwork_to_artist.artwork_cd_id'=> 1})->count }
23 q{... but chaining off of a virtual view using join doesn't work};
ec781604 24
25my $book_rs = $schema->resultset ('BooksInLibrary')->search ({}, { join => 'owner' });
26
27is_same_sql_bind (
28 $book_rs->as_subselect_rs->as_query,
8273e845 29 '(SELECT me.id, me.source, me.owner, me.title, me.price
ec781604 30 FROM (
31 SELECT me.id, me.source, me.owner, me.title, me.price
32 FROM books me
33 JOIN owners owner ON owner.id = me.owner
34 WHERE ( source = ? )
35 ) me
36 )',
0e773352 37 [ [ { sqlt_datatype => 'varchar', sqlt_size => 100, dbic_colname => 'source' }
38 => 'Library' ] ],
ec781604 39 'Resultset-class attributes do not seep outside of the subselect',
40);
41
ff46b7b3 42is_same_sql_bind(
43 $schema->resultset('CD')->search ({}, {
44 rows => 2,
45 join => [ 'genre', { artist => 'cds' } ],
46 distinct => 1,
47 columns => {
48 title => 'me.title',
49 artist__name => 'artist.name',
50 genre__name => 'genre.name',
51 cds_for_artist => \ '(SELECT COUNT(*) FROM cds WHERE cd.artist = artist.id)',
52 },
53 order_by => { -desc => 'me.year' },
54 })->count_rs->as_query,
55 '(
56 SELECT COUNT( * )
57 FROM (
58 SELECT artist.name AS artist__name, (SELECT COUNT(*) FROM cds WHERE cd.artist = artist.id), genre.name AS genre__name, me.title, me.year
59 FROM cd me
60 LEFT JOIN genre genre
61 ON genre.genreid = me.genreid
62 JOIN artist artist ON artist.artistid = me.artist
63 GROUP BY artist.name, (SELECT COUNT(*) FROM cds WHERE cd.artist = artist.id), genre.name, me.title, me.year
64 LIMIT ?
65 ) me
66 )',
67 [ [{ sqlt_datatype => 'integer' } => 2 ] ],
68);
69
e4bb6727 70done_testing;