remove trailing whitespace

[gitmo/Moose.git] / t / 010_basics / 005_override_augment_inner_super.t

diff --git a/t/010_basics/005_override_augment_inner_super.t b/t/010_basics/005_override_augment_inner_super.t
index 2d4a330..295601e 100644 (file)
--- a/t/010_basics/005_override_augment_inner_super.t
+++ b/t/010_basics/005_override_augment_inner_super.t
@@ -10,23 +10,23 @@ use Test::More tests => 5;
 {
     package Foo;
     use Moose;
-    
+
     sub foo { 'Foo::foo(' . (inner() || '') . ')' };
     sub bar { 'Foo::bar(' . (inner() || '') . ')' }
-    
+
     package Bar;
     use Moose;
-    
+
     extends 'Foo';
-    
+
     augment  'foo' => sub { 'Bar::foo' };
-    override 'bar' => sub { 'Bar::bar -> ' . super() };    
-    
+    override 'bar' => sub { 'Bar::bar -> ' . super() };
+
     package Baz;
     use Moose;
-    
+
     extends 'Bar';
-    
+
     override 'foo' => sub { 'Baz::foo -> ' . super() };
     augment  'bar' => sub { 'Baz::bar' };
 }
@@ -38,33 +38,33 @@ isa_ok($baz, 'Foo');
 
 =pod
 
-Let em clarify what is happening here. Baz::foo is calling 
-super(), which calls Bar::foo, which is an augmented sub 
-that calls Foo::foo, then calls inner() which actually 
-then calls Bar::foo. Confusing I know,.. but this is 
+Let em clarify what is happening here. Baz::foo is calling
+super(), which calls Bar::foo, which is an augmented sub
+that calls Foo::foo, then calls inner() which actually
+then calls Bar::foo. Confusing I know,.. but this is
 *exactly* what is it supposed to do :)
 
 =cut
 
-is($baz->foo, 
-  'Baz::foo -> Foo::foo(Bar::foo)', 
+is($baz->foo,
+  'Baz::foo -> Foo::foo(Bar::foo)',
   '... got the right value from mixed augment/override foo');
 
 =pod
 
 Allow me to clarify this one now ...
 
-Since Baz::bar is an augment routine, it needs to find the 
+Since Baz::bar is an augment routine, it needs to find the
 correct inner() to be called by. In this case it is Foo::bar.
-However, Bar::bar is inbetween us, so it should actually be
+However, Bar::bar is in-between us, so it should actually be
 called first. Bar::bar is an overriden sub, and calls super()
-which in turn then calls our Foo::bar, which calls inner(), 
+which in turn then calls our Foo::bar, which calls inner(),
 which calls Baz::bar.
 
 Confusing I know, but it is correct :)
 
 =cut
 
-is($baz->bar, 
-    'Bar::bar -> Foo::bar(Baz::bar)', 
+is($baz->bar,
+    'Bar::bar -> Foo::bar(Baz::bar)',
     '... got the right value from mixed augment/override bar');