The size of a character in C is per definition 1

diff --git a/Configure b/Configure
index f4d9cfb..60eac75 100755 (executable)
--- a/Configure
+++ b/Configure
@@ -30,7 +30,7 @@
 
 # $Id: Head.U 6 2006-08-25 22:21:46Z rmanfredi $
 #
-# Generated on Mon Mar 29 10:12:43 CEST 2010 [metaconfig 3.5 PL0]
+# Generated on Fri May 21 07:59:07 CEST 2010 [metaconfig 3.5 PL0]
 # (with additional metaconfig patches by perlbug@perl.org)
 
 cat >c1$$ <<EOF
@@ -18862,39 +18862,9 @@ esac
 : set the base revision
 baserev=5.0
 
-: check for length of character
-echo " "
-case "$charsize" in
-'')
-       echo "Checking to see how big your characters are (hey, you never know)..." >&4
-       $cat >try.c <<EOCP
-#include <stdio.h>
-#$i_stdlib I_STDLIB
-#ifdef I_STDLIB
-#include <stdlib.h>
-#endif
-int main()
-{
-    printf("%d\n", (int)sizeof(char));
-    exit(0);
-}
-EOCP
-       set try
-       if eval $compile_ok; then
-               dflt=`$run ./try`
-       else
-               dflt='1'
-               echo "(I can't seem to compile the test program.  Guessing...)"
-       fi
-       ;;
-*)
-       dflt="$charsize"
-       ;;
-esac
-rp="What is the size of a character (in bytes)?"
-. ./myread
-charsize="$ans"
-$rm_try
+: length of character in bytes. Is always 1, otherwise it isnt C
+: This used to be a test using sizeof
+charsize=1
 
 : Check for the number of bits in a character
 case "$charbits" in