as using square brackets--instead it's the same as creating
a list of references!
- @list = (\$a, \$b, \$c);
- @list = \($a, $b, $c); # same thing!
+ @list = (\$a, \@b, \%c);
+ @list = \($a, @b, %c); # same thing!
+
+As a special case, C<\(@foo)> returns a list of references to the contents
+of C<@foo>, not a reference to C<@foo> itself. Likewise for C<%foo>.
=item 3.
#!./perl
-print "1..41\n";
+print "1..47\n";
# Test glob operations.
package WHATEVER;
foo WHATEVER "ok 38\n";
+#
+# test the \(@foo) construct
+#
+package main;
+@foo = (1,2,3);
+@bar = \(@foo);
+@baz = \(1,@foo,@bar);
+print @bar == 3 ? "ok 39\n" : "not ok 39\n";
+print grep(ref($_), @bar) == 3 ? "ok 40\n" : "not ok 40\n";
+print @baz == 3 ? "ok 41\n" : "not ok 41\n";
+
+my(@fuu) = (1,2,3);
+my(@baa) = \(@fuu);
+my(@bzz) = \(1,@fuu,@baa);
+print @baa == 3 ? "ok 42\n" : "not ok 42\n";
+print grep(ref($_), @baa) == 3 ? "ok 43\n" : "not ok 43\n";
+print @bzz == 3 ? "ok 44\n" : "not ok 44\n";
+
package FINALE;
{
- $ref3 = bless ["ok 41\n"]; # package destruction
- my $ref2 = bless ["ok 40\n"]; # lexical destruction
- local $ref1 = bless ["ok 39\n"]; # dynamic destruction
+ $ref3 = bless ["ok 47\n"]; # package destruction
+ my $ref2 = bless ["ok 46\n"]; # lexical destruction
+ local $ref1 = bless ["ok 45\n"]; # dynamic destruction
1; # flush any temp values on stack
}