Message-Id: <
20071117230212.20bef697.hio@hio.jp>
Date: Sat, 17 Nov 2007 23:02:12 +0900
p4raw-id: //depot/perl@32366
A new prototype character has been added. C<_> is equivalent to C<$> but
defaults to C<$_> if the corresponding argument isn't supplied. (both C<$>
-and <_> denote a scalar). Due to the optional nature of the argument, you
+and C<_> denote a scalar). Due to the optional nature of the argument, you
can only use it at the end of a prototype, or before a semicolon.
This has a small incompatible consequence: the prototype() function has