The behavior remains unaffected when C<not> is not followed by parentheses.
+=item Semantics of bareword prototype C<(*)> have changed
+
+Arguments prototyped as C<*> will now be visible within the subroutine
+as either a simple scalar or as a reference to a typeglob. Perl 5.005
+always coerced simple scalar arguments to a typeglob, which wasn't useful
+in situations where the subroutine must distinguish between a simple
+scalar and a typeglob. See L<perlsub/Prototypes>.
+
=back
=head2 C Source Incompatibilities
unbackslashed C<@> or C<%> eats all remaining arguments, and forces
list context. An argument represented by C<$> forces scalar context. An
C<&> requires an anonymous subroutine, which, if passed as the first
-argument, does not require the C<sub> keyword or a subsequent comma. A
-C<*> allows the subroutine to accept a bareword, constant, scalar expression,
+argument, does not require the C<sub> keyword or a subsequent comma.
+
+A C<*> allows the subroutine to accept a bareword, constant, scalar expression,
typeglob, or a reference to a typeglob in that slot. The value will be
available to the subroutine either as a simple scalar, or (in the latter
-two cases) as a reference to the typeglob.
+two cases) as a reference to the typeglob. If you wish to always convert
+such arguments to a typeglob reference, use Symbol::qualify_to_ref() as
+follows:
+
+ use Symbol 'qualify_to_ref';
+
+ sub foo (*) {
+ my $fh = qualify_to_ref(shift, caller);
+ ...
+ }
A semicolon separates mandatory arguments from optional arguments.
It is redundant before C<@> or C<%>, which gobble up everything else.