Message-Id: <
20050717112557.5921.BQW10602@nifty.com>
p4raw-id: //depot/perl@25165
the example above is not C<m//x>, but rather C<m//> with no C</x>
modifier. So the embedded C<#> is interpreted as a literal C<#>.
+Also no attention is paid to C<\c\> during this search.
+Thus the second C<\> in C<qq/\c\/> is interpreted as a part of C<\/>,
+and the following C</> is not recognized as a delimiter.
+Instead, use C<\034> or C<\x1c> at the end of quoted constructs.
+
=item Removal of backslashes before delimiters
During the second pass, text between the starting and ending