else
lex_brackstack[lex_brackets++] = XOPERATOR;
s = skipspace(s);
- if (*s == '}') {
- if (expect == XSTATE) {
- lex_brackstack[lex_brackets-1] = XSTATE;
- break;
- }
+ if (*s == '}')
OPERATOR(HASHBRACK);
- }
/* This hack serves to disambiguate a pair of curlies
* as being a block or an anon hash. Normally, expectation
* determines that, but in cases where we're not in a