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diff --git a/pod/perldata.pod b/pod/perldata.pod
index ac444fa..50b6858 100644
--- a/pod/perldata.pod
+++ b/pod/perldata.pod
@@ -259,7 +259,7 @@ of sixteen buckets has been touched, and presumably contains all
 10,000 of your items.  This isn't supposed to happen.
 
 You can preallocate space for a hash by assigning to the keys() function.
-This rounds up the allocated bucked to the next power of two:
+This rounds up the allocated buckets to the next power of two:
 
     keys(%users) = 1000;		# allocate 1024 buckets
 
@@ -303,7 +303,8 @@ price is $Z<>100."
     print "The price is $Price.\n";	# interpreted
 
 As in some shells, you can enclose the variable name in braces to
-disambiguate it from following alphanumerics.  You must also do
+disambiguate it from following alphanumerics (and underscores).
+You must also do
 this when interpolating a variable into a string to separate the
 variable name from a following double-colon or an apostrophe, since
 these would be otherwise treated as a package separator:
@@ -461,6 +462,22 @@ from each line manually:
 	down from the door where it began.
     FINIS
 
+If you use a here-doc within a delimited construct, such as in C<s///eg>,
+the quoted material must come on the lines following the final delimiter.
+So instead of
+
+    s/this/<<E . 'that'
+    the other
+    E
+     . 'more '/eg;
+
+you have to write
+
+    s/this/<<E . 'that' 
+     . 'more '/eg; 
+    the other 
+    E 
+
 =head2 List value constructors
 
 List values are denoted by separating individual values by commas
@@ -523,6 +540,15 @@ has no effect.  Thus ((),(),()) is equivalent to ().  Similarly,
 interpolating an array with no elements is the same as if no
 array had been interpolated at that point.
 
+This interpolation combines with the facts that the opening
+and closing parentheses are optional (except necessary for
+precedence) and lists may end with an optional comma to mean that
+multiple commas within lists are legal syntax. The list C<1,,3> is a
+concatenation of two lists, C<1,> and C<3>, the first of which ends
+with that optional comma.  C<1,,3> is C<(1,),(3)> is C<1,3> (And
+similarly for C<1,,,3> is C<(1,),(,),3> is C<1,3> and so on.)  Not that
+we'd advise you to use this obfuscation.
+
 A list value may also be subscripted like a normal array.  You must
 put the list in parentheses to avoid ambiguity.  For example: