=over 4
=item *
+
\d is a digit and represents [0-9]
=item *
+
\s is a whitespace character and represents [\ \t\r\n\f]
=item *
+
\w is a word character (alphanumeric or _) and represents [0-9a-zA-Z_]
=item *
+
\D is a negated \d; it represents any character but a digit [^0-9]
=item *
+
\S is a negated \s; it represents any non-whitespace character [^\s]
=item *
+
\W is a negated \w; it represents any non-word character [^\w]
=item *
+
The period '.' matches any character but "\n"
=back
=over 4
=item *
+
no modifiers (//): Default behavior. C<'.'> matches any character
except C<"\n">. C<^> matches only at the beginning of the string and
C<$> matches only at the end or before a newline at the end.
=item *
+
s modifier (//s): Treat string as a single long line. C<'.'> matches
any character, even C<"\n">. C<^> matches only at the beginning of
the string and C<$> matches only at the end or before a newline at the
end.
=item *
+
m modifier (//m): Treat string as a set of multiple lines. C<'.'>
matches any character except C<"\n">. C<^> and C<$> are able to match
at the start or end of I<any> line within the string.
=item *
+
both s and m modifiers (//sm): Treat string as a single long line, but
detect multiple lines. C<'.'> matches any character, even
C<"\n">. C<^> and C<$>, however, are able to match at the start or end
=over 4
-=item 0 Start with the first letter in the string 'a'.
+=item 0
+
+Start with the first letter in the string 'a'.
+
+=item 1
+
+Try the first alternative in the first group 'abd'.
+
+=item 2
-=item 1 Try the first alternative in the first group 'abd'.
+Match 'a' followed by 'b'. So far so good.
-=item 2 Match 'a' followed by 'b'. So far so good.
+=item 3
-=item 3 'd' in the regexp doesn't match 'c' in the string - a dead
+'d' in the regexp doesn't match 'c' in the string - a dead
end. So backtrack two characters and pick the second alternative in
the first group 'abc'.
-=item 4 Match 'a' followed by 'b' followed by 'c'. We are on a roll
+=item 4
+
+Match 'a' followed by 'b' followed by 'c'. We are on a roll
and have satisfied the first group. Set $1 to 'abc'.
-=item 5 Move on to the second group and pick the first alternative
+=item 5
+
+Move on to the second group and pick the first alternative
'df'.
-=item 6 Match the 'd'.
+=item 6
+
+Match the 'd'.
-=item 7 'f' in the regexp doesn't match 'e' in the string, so a dead
+=item 7
+
+'f' in the regexp doesn't match 'e' in the string, so a dead
end. Backtrack one character and pick the second alternative in the
second group 'd'.
-=item 8 'd' matches. The second grouping is satisfied, so set $2 to
+=item 8
+
+'d' matches. The second grouping is satisfied, so set $2 to
'd'.
-=item 9 We are at the end of the regexp, so we are done! We have
+=item 9
+
+We are at the end of the regexp, so we are done! We have
matched 'abcd' out of the string "abcde".
=back
/(ab(cd|ef)((gi)|j))/;
1 2 34
-so that if the regexp matched, e.g., C<$2> would contain 'cd' or 'ef'.
-For convenience, perl sets C<$+> to the highest numbered C<$1>, C<$2>,
-... that got assigned.
+so that if the regexp matched, e.g., C<$2> would contain 'cd' or 'ef'. For
+convenience, perl sets C<$+> to the string held by the highest numbered
+C<$1>, C<$2>, ... that got assigned (and, somewhat related, C<$^N> to the
+value of the C<$1>, C<$2>, ... most-recently assigned; i.e. the C<$1>,
+C<$2>, ... associated with the rightmost closing parenthesis used in the
+match).
Closely associated with the matching variables C<$1>, C<$2>, ... are
the B<backreferences> C<\1>, C<\2>, ... . Backreferences are simply
=over 4
-=item * C<a?> = match 'a' 1 or 0 times
+=item *
+
+C<a?> = match 'a' 1 or 0 times
+
+=item *
+
+C<a*> = match 'a' 0 or more times, i.e., any number of times
-=item * C<a*> = match 'a' 0 or more times, i.e., any number of times
+=item *
-=item * C<a+> = match 'a' 1 or more times, i.e., at least once
+C<a+> = match 'a' 1 or more times, i.e., at least once
-=item * C<a{n,m}> = match at least C<n> times, but not more than C<m>
+=item *
+
+C<a{n,m}> = match at least C<n> times, but not more than C<m>
times.
-=item * C<a{n,}> = match at least C<n> or more times
+=item *
-=item * C<a{n}> = match exactly C<n> times
+C<a{n,}> = match at least C<n> or more times
+
+=item *
+
+C<a{n}> = match exactly C<n> times
=back
=over 4
=item *
+
Principle 0: Taken as a whole, any regexp will be matched at the
earliest possible position in the string.
=item *
+
Principle 1: In an alternation C<a|b|c...>, the leftmost alternative
that allows a match for the whole regexp will be the one used.
=item *
+
Principle 2: The maximal matching quantifiers C<?>, C<*>, C<+> and
C<{n,m}> will in general match as much of the string as possible while
still allowing the whole regexp to match.
=item *
+
Principle 3: If there are two or more elements in a regexp, the
leftmost greedy quantifier, if any, will match as much of the string
as possible while still allowing the whole regexp to match. The next
=over 4
-=item * C<a??> = match 'a' 0 or 1 times. Try 0 first, then 1.
+=item *
+
+C<a??> = match 'a' 0 or 1 times. Try 0 first, then 1.
-=item * C<a*?> = match 'a' 0 or more times, i.e., any number of times,
+=item *
+
+C<a*?> = match 'a' 0 or more times, i.e., any number of times,
but as few times as possible
-=item * C<a+?> = match 'a' 1 or more times, i.e., at least once, but
+=item *
+
+C<a+?> = match 'a' 1 or more times, i.e., at least once, but
as few times as possible
-=item * C<a{n,m}?> = match at least C<n> times, not more than C<m>
+=item *
+
+C<a{n,m}?> = match at least C<n> times, not more than C<m>
times, as few times as possible
-=item * C<a{n,}?> = match at least C<n> times, but as few times as
+=item *
+
+C<a{n,}?> = match at least C<n> times, but as few times as
possible
-=item * C<a{n}?> = match exactly C<n> times. Because we match exactly
+=item *
+
+C<a{n}?> = match exactly C<n> times. Because we match exactly
C<n> times, C<a{n}?> is equivalent to C<a{n}> and is just there for
notational consistency.
=over 4
=item *
+
Principle 3: If there are two or more elements in a regexp, the
leftmost greedy (non-greedy) quantifier, if any, will match as much
(little) of the string as possible while still allowing the whole
=over 4
-=item 0 Start with the first letter in the string 't'.
+=item 0
+
+Start with the first letter in the string 't'.
+
+=item 1
-=item 1 The first quantifier '.*' starts out by matching the whole
+The first quantifier '.*' starts out by matching the whole
string 'the cat in the hat'.
-=item 2 'a' in the regexp element 'at' doesn't match the end of the
+=item 2
+
+'a' in the regexp element 'at' doesn't match the end of the
string. Backtrack one character.
-=item 3 'a' in the regexp element 'at' still doesn't match the last
+=item 3
+
+'a' in the regexp element 'at' still doesn't match the last
letter of the string 't', so backtrack one more character.
-=item 4 Now we can match the 'a' and the 't'.
+=item 4
-=item 5 Move on to the third element '.*'. Since we are at the end of
+Now we can match the 'a' and the 't'.
+
+=item 5
+
+Move on to the third element '.*'. Since we are at the end of
the string and '.*' can match 0 times, assign it the empty string.
-=item 6 We are done!
+=item 6
+
+We are done!
=back
=over 4
-=item * specifying the task in detail,
+=item *
-=item * breaking down the problem into smaller parts,
+specifying the task in detail,
-=item * translating the small parts into regexps,
+=item *
-=item * combining the regexps,
+breaking down the problem into smaller parts,
-=item * and optimizing the final combined regexp.
+=item *
+
+translating the small parts into regexps,
+
+=item *
+
+combining the regexps,
+
+=item *
+
+and optimizing the final combined regexp.
=back
print "\N{sigma} is Greek sigma\n";
A list of full names is found in the file Names.txt in the
-lib/perl5/5.6.0/unicode directory.
+lib/perl5/5.X.X/unicore directory.
The answer to requirement 2), as of 5.6.0, is that if a regexp
contains Unicode characters, the string is searched as a sequence of
$x =~ /^\p{IsLower}/; # doesn't match, lowercase char class
$x =~ /^\P{IsLower}/; # matches, char class sans lowercase
-If a C<name> is just one letter, the braces can be dropped. For
-instance, C<\pM> is the character class of Unicode 'marks'. Here is
-the association between some Perl named classes and the traditional
-Unicode classes:
+Here is the association between some Perl named classes and the
+traditional Unicode classes:
- Perl class name Unicode class name
+ Perl class name Unicode class name or regular expression
- IsAlpha Lu, Ll, or Lo
- IsAlnum Lu, Ll, Lo, or Nd
- IsASCII $code le 127
- IsCntrl C
+ IsAlpha /^[LM]/
+ IsAlnum /^[LMN]/
+ IsASCII $code <= 127
+ IsCntrl /^C/
+ IsBlank $code =~ /^(0020|0009)$/ || /^Z[^lp]/
IsDigit Nd
- IsGraph [^C] and $code ne "0020"
+ IsGraph /^([LMNPS]|Co)/
IsLower Ll
- IsPrint [^C]
- IsPunct P
- IsSpace Z, or ($code lt "0020" and chr(hex $code) is a \s)
- IsUpper Lu
- IsWord Lu, Ll, Lo, Nd or $code eq "005F"
+ IsPrint /^([LMNPS]|Co|Zs)/
+ IsPunct /^P/
+ IsSpace /^Z/ || ($code =~ /^(0009|000A|000B|000C|000D)$/
+ IsSpacePerl /^Z/ || ($code =~ /^(0009|000A|000C|000D)$/
+ IsUpper /^L[ut]/
+ IsWord /^[LMN]/ || $code eq "005F"
IsXDigit $code =~ /^00(3[0-9]|[46][1-6])$/
-For a full list of Perl class names, consult the mktables.PL program
-in the lib/perl5/5.6.0/unicode directory.
+You can also use the official Unicode class names with the C<\p> and
+C<\P>, like C<\p{L}> for Unicode 'letters', or C<\p{Lu}> for uppercase
+letters, or C<\P{Nd}> for non-digits. If a C<name> is just one
+letter, the braces can be dropped. For instance, C<\pM> is the
+character class of Unicode 'marks', for example accent marks.
+For the full list see L<perlunicode>.
+
+The Unicode has also been separated into various sets of charaters
+which you can test with C<\p{In...}> (in) and C<\P{In...}> (not in),
+for example C<\p{InLatin}>, C<\p{InGreek}>, or C<\P{InKatakana}>.
+For the full list see L<perlunicode>.
C<\X> is an abbreviation for a character class sequence that includes
the Unicode 'combining character sequences'. A 'combining character
atop it, as in the word Angstrom. C<\X> is equivalent to C<\PM\pM*}>,
i.e., a non-mark followed by one or more marks.
+For the the full and latest information about Unicode see the latest
+Unicode standard, or the Unicode Consortium's website http://www.unicode.org/
+
As if all those classes weren't enough, Perl also defines POSIX style
character classes. These have the form C<[:name:]>, with C<name> the
name of the POSIX class. The POSIX classes are C<alpha>, C<alnum>,
# prints 'Hi Mom!'
$x =~ /aaa(?{print "Hi Mom!";})def/; # doesn't match,
# no 'Hi Mom!'
+
+Pay careful attention to the next example:
+
$x =~ /abc(?{print "Hi Mom!";})ddd/; # doesn't match,
# no 'Hi Mom!'
+ # but why not?
+
+At first glance, you'd think that it shouldn't print, because obviously
+the C<ddd> isn't going to match the target string. But look at this
+example:
+
+ $x =~ /abc(?{print "Hi Mom!";})[d]dd/; # doesn't match,
+ # but _does_ print
+
+Hmm. What happened here? If you've been following along, you know that
+the above pattern should be effectively the same as the last one --
+enclosing the d in a character class isn't going to change what it
+matches. So why does the first not print while the second one does?
+
+The answer lies in the optimizations the REx engine makes. In the first
+case, all the engine sees are plain old characters (aside from the
+C<?{}> construct). It's smart enough to realize that the string 'ddd'
+doesn't occur in our target string before actually running the pattern
+through. But in the second case, we've tricked it into thinking that our
+pattern is more complicated than it is. It takes a look, sees our
+character class, and decides that it will have to actually run the
+pattern to determine whether or not it matches, and in the process of
+running it hits the print statement before it discovers that we don't
+have a match.
+
+To take a closer look at how the engine does optimizations, see the
+section L<"Pragmas and debugging"> below.
+
+More fun with C<?{}>:
+
$x =~ /(?{print "Hi Mom!";})/; # matches,
# prints 'Hi Mom!'
$x =~ /(?{$c = 1;})(?{print "$c";})/; # matches,