=head1 DESCRIPTION
This page describes the syntax of regular expressions in Perl. For a
-description of how to actually I<use> regular expressions in matching
-operations, plus various examples of the same, see C<m//> and C<s///> in
-L<perlop>.
+description of how to I<use> regular expressions in matching
+operations, plus various examples of the same, see discussion
+of C<m//>, C<s///>, and C<??> in L<perlop/Regexp Quote-Like Operators>.
-The matching operations can
-have various modifiers, some of which relate to the interpretation of
-the regular expression inside. These are:
+The matching operations can have various modifiers. The modifiers
+that relate to the interpretation of the regular expression inside
+are listed below. For the modifiers that alter the way regular expression
+is used by Perl, see L<perlop/Regexp Quote-Like Operators>.
- i Do case-insensitive pattern matching.
- m Treat string as multiple lines.
- s Treat string as single line.
- x Extend your pattern's legibility with whitespace and comments.
+=over 4
+
+=item i
+
+Do case-insensitive pattern matching.
+
+If C<use locale> is in effect, the case map is taken from the current
+locale. See L<perllocale>.
+
+=item m
+
+Treat string as multiple lines. That is, change "^" and "$" from matching
+at only the very start or end of the string to the start or end of any
+line anywhere within the string,
+
+=item s
+
+Treat string as single line. That is, change "." to match any character
+whatsoever, even a newline, which it normally would not match.
+
+The C</s> and C</m> modifiers both override the C<$*> setting. That is, no matter
+what C<$*> contains, C</s> without C</m> will force "^" to match only at the
+beginning of the string and "$" to match only at the end (or just before a
+newline at the end) of the string. Together, as /ms, they let the "." match
+any character whatsoever, while yet allowing "^" and "$" to match,
+respectively, just after and just before newlines within the string.
+
+=item x
+
+Extend your pattern's legibility by permitting whitespace and comments.
+
+=back
These are usually written as "the C</x> modifier", even though the delimiter
in question might not actually be a slash. In fact, any of these
the new C<(?...)> construct. See below.
The C</x> modifier itself needs a little more explanation. It tells
-the regular expression parser to ignore whitespace that is not
-backslashed or within a character class. You can use this to break up
+the regular expression parser to ignore whitespace that is neither
+backslashed nor within a character class. You can use this to break up
your regular expression into (slightly) more readable parts. The C<#>
character is also treated as a metacharacter introducing a comment,
-just as in ordinary Perl code. Taken together, these features go a
-long way towards making Perl 5 a readable language. See the C comment
-deletion code in L<perlop>.
+just as in ordinary Perl code. This also means that if you want real
+whitespace or C<#> characters in the pattern (outside of a character
+class, where they are unaffected by C</x>), that you'll either have to
+escape them or encode them using octal or hex escapes. Taken together,
+these features go a long way towards making Perl's regular expressions
+more readable. Note that you have to be careful not to include the
+pattern delimiter in the comment--perl has no way of knowing you did
+not intend to close the pattern early. See the C-comment deletion code
+in L<perlop>.
=head2 Regular Expressions
The patterns used in pattern matching are regular expressions such as
-those supplied in the Version 8 regexp routines. (In fact, the
+those supplied in the Version 8 regex routines. (In fact, the
routines are derived (distantly) from Henry Spencer's freely
redistributable reimplementation of the V8 routines.)
See L<Version 8 Regular Expressions> for details.
() Grouping
[] Character class
-By default, the "^" character is guaranteed to match only at the
-beginning of the string, the "$" character only at the end (or before the
+By default, the "^" character is guaranteed to match at only the
+beginning of the string, the "$" character at only the end (or before the
newline at the end) and Perl does certain optimizations with the
assumption that the string contains only one line. Embedded newlines
will not be matched by "^" or "$". You may, however, wish to treat a
newline within the string, and "$" will match before any newline. At the
cost of a little more overhead, you can do this by using the /m modifier
on the pattern match operator. (Older programs did this by setting C<$*>,
-but this practice is deprecated in Perl 5.)
+but this practice is now deprecated.)
To facilitate multi-line substitutions, the "." character never matches a
-newline unless you use the C</s> modifier, which tells Perl to pretend
+newline unless you use the C</s> modifier, which in effect tells Perl to pretend
the string is a single line--even if it isn't. The C</s> modifier also
overrides the setting of C<$*>, in case you have some (badly behaved) older
code that sets it in another module.
to integral values less than 65536.
By default, a quantified subpattern is "greedy", that is, it will match as
-many times as possible without causing the rest pattern not to match. The
-standard quantifiers are all "greedy", in that they match as many
-occurrences as possible (given a particular starting location) without
-causing the pattern to fail. If you want it to match the minimum number
-of times possible, follow the quantifier with a "?" after any of them.
-Note that the meanings don't change, just the "gravity":
+many times as possible (given a particular starting location) while still
+allowing the rest of the pattern to match. If you want it to match the
+minimum number of times possible, follow the quantifier with a "?". Note
+that the meanings don't change, just the "greediness":
*? Match 0 or more times
+? Match 1 or more times
{n,}? Match at least n times
{n,m}? Match at least n but not more than m times
-Since patterns are processed as double quoted strings, the following
+Because patterns are processed as double quoted strings, the following
also work:
- \t tab
- \n newline
- \r return
- \f form feed
- \v vertical tab, whatever that is
- \a alarm (bell)
- \e escape (think troff)
+ \t tab (HT, TAB)
+ \n newline (LF, NL)
+ \r return (CR)
+ \f form feed (FF)
+ \a alarm (bell) (BEL)
+ \e escape (think troff) (ESC)
\033 octal char (think of a PDP-11)
\x1B hex char
\c[ control char
\L lowercase till \E (think vi)
\U uppercase till \E (think vi)
\E end case modification (think vi)
- \Q quote regexp metacharacters till \E
+ \Q quote (disable) pattern metacharacters till \E
+
+If C<use locale> is in effect, the case map used by C<\l>, C<\L>, C<\u>
+and C<\U> is taken from the current locale. See L<perllocale>.
+
+You cannot include a literal C<$> or C<@> within a C<\Q> sequence.
+An unescaped C<$> or C<@> interpolates the corresponding variable,
+while escaping will cause the literal string C<\$> to be matched.
+You'll need to write something like C<m/\Quser\E\@\Qhost/>.
In addition, Perl defines the following:
\d Match a digit character
\D Match a non-digit character
-Note that C<\w> matches a single alphanumeric character, not a whole
-word. To match a word you'd need to say C<\w+>. You may use C<\w>,
-C<\W>, C<\s>, C<\S>, C<\d> and C<\D> within character classes (though not
-as either end of a range).
+A C<\w> matches a single alphanumeric character, not a whole
+word. To match a word you'd need to say C<\w+>. If C<use locale> is in
+effect, the list of alphabetic characters generated by C<\w> is taken
+from the current locale. See L<perllocale>. You may use C<\w>, C<\W>,
+C<\s>, C<\S>, C<\d>, and C<\D> within character classes (though not as
+either end of a range).
Perl defines the following zero-width assertions:
\b Match a word boundary
\B Match a non-(word boundary)
\A Match only at beginning of string
- \Z Match only at end of string (or before newline at the end)
- \G Match only where previous m//g left off
+ \Z Match only at end of string, or before newline at the end
+ \z Match only at end of string
+ \G Match only where previous m//g left off (works only with /g)
A word boundary (C<\b>) is defined as a spot between two characters that
-has a C<\w> on one side of it and and a C<\W> on the other side of it (in
+has a C<\w> on one side of it and a C<\W> on the other side of it (in
either order), counting the imaginary characters off the beginning and
end of the string as matching a C<\W>. (Within character classes C<\b>
represents backspace rather than a word boundary.) The C<\A> and C<\Z> are
-just like "^" and "$" except that they won't match multiple times when the
+just like "^" and "$", except that they won't match multiple times when the
C</m> modifier is used, while "^" and "$" will match at every internal line
boundary. To match the actual end of the string, not ignoring newline,
-you can use C<\Z(?!\n)>.
+you can use C<\z>. The C<\G> assertion can be used to chain global
+matches (using C<m//g>), as described in
+L<perlop/"Regexp Quote-Like Operators">.
+
+It is also useful when writing C<lex>-like scanners, when you have several
+patterns that you want to match against consequent substrings of your
+string, see the previous reference.
+The actual location where C<\G> will match can also be influenced
+by using C<pos()> as an lvalue. See L<perlfunc/pos>.
-When the bracketing construct C<( ... )> is used, \<digit> matches the
+When the bracketing construct C<( ... )> is used, \E<lt>digitE<gt> matches the
digit'th substring. Outside of the pattern, always use "$" instead of "\"
-in front of the digit. (The \<digit> notation can on rare occasion work
+in front of the digit. (While the \E<lt>digitE<gt> notation can on rare occasion work
outside the current pattern, this should not be relied upon. See the
-WARNING below.) The scope of $<digit> (and C<$`>, C<$&>, and C<$')>
+WARNING below.) The scope of $E<lt>digitE<gt> (and C<$`>, C<$&>, and C<$'>)
extends to the end of the enclosing BLOCK or eval string, or to the next
successful pattern match, whichever comes first. If you want to use
-parentheses to delimit subpattern (e.g. a set of alternatives) without
-saving it as a subpattern, follow the ( with a ?.
+parentheses to delimit a subpattern (e.g., a set of alternatives) without
+saving it as a subpattern, follow the ( with a ?:.
You may have as many parentheses as you wish. If you have more
than 9 substrings, the variables $10, $11, ... refer to the
corresponding substring. Within the pattern, \10, \11, etc. refer back
-to substrings if there have been at least that many left parens before
+to substrings if there have been at least that many left parentheses before
the backreference. Otherwise (for backward compatibility) \10 is the
same as \010, a backspace, and \11 the same as \011, a tab. And so
on. (\1 through \9 are always backreferences.)
C<$+> returns whatever the last bracket match matched. C<$&> returns the
-entire matched string. ($0 used to return the same thing, but not any
+entire matched string. (C<$0> used to return the same thing, but not any
more.) C<$`> returns everything before the matched string. C<$'> returns
everything after the matched string. Examples:
$seconds = $3;
}
-You will note that all backslashed metacharacters in Perl are
-alphanumeric, such as C<\b>, C<\w>, C<\n>. Unlike some other regular expression
-languages, there are no backslashed symbols that aren't alphanumeric.
-So anything that looks like \\, \(, \), \<, \>, \{, or \} is always
-interpreted as a literal character, not a metacharacter. This makes it
-simple to quote a string that you want to use for a pattern but that
-you are afraid might contain metacharacters. Simply quote all the
+Once perl sees that you need one of C<$&>, C<$`> or C<$'> anywhere in
+the program, it has to provide them on each and every pattern match.
+This can slow your program down. The same mechanism that handles
+these provides for the use of $1, $2, etc., so you pay the same price
+for each pattern that contains capturing parentheses. But if you never
+use $&, etc., in your script, then patterns I<without> capturing
+parentheses won't be penalized. So avoid $&, $', and $` if you can,
+but if you can't (and some algorithms really appreciate them), once
+you've used them once, use them at will, because you've already paid
+the price. As of 5.005, $& is not so costly as the other two.
+
+Backslashed metacharacters in Perl are
+alphanumeric, such as C<\b>, C<\w>, C<\n>. Unlike some other regular
+expression languages, there are no backslashed symbols that aren't
+alphanumeric. So anything that looks like \\, \(, \), \E<lt>, \E<gt>,
+\{, or \} is always interpreted as a literal character, not a
+metacharacter. This was once used in a common idiom to disable or
+quote the special meanings of regular expression metacharacters in a
+string that you want to use for a pattern. Simply quote all
non-alphanumeric characters:
$pattern =~ s/(\W)/\\$1/g;
-You can also use the built-in quotemeta() function to do this.
-An even easier way to quote metacharacters right in the match operator
-is to say
+Now it is much more common to see either the quotemeta() function or
+the C<\Q> escape sequence used to disable all metacharacters' special
+meanings like this:
/$unquoted\Q$quoted\E$unquoted/
-Perl 5 defines a consistent extension syntax for regular expressions.
-The syntax is a pair of parens with a question mark as the first thing
-within the parens (this was a syntax error in Perl 4). The character
-after the question mark gives the function of the extension. Several
-extensions are already supported:
+Perl defines a consistent extension syntax for regular expressions.
+The syntax is a pair of parentheses with a question mark as the first
+thing within the parentheses (this was a syntax error in older
+versions of Perl). The character after the question mark gives the
+function of the extension. Several extensions are already supported:
=over 10
-=item (?#text)
+=item C<(?#text)>
A comment. The text is ignored. If the C</x> switch is used to enable
-whitespace formatting, a simple C<#> will suffice.
+whitespace formatting, a simple C<#> will suffice. Note that perl closes
+the comment as soon as it sees a C<)>, so there is no way to put a literal
+C<)> in the comment.
-=item (?:regexp)
+=item C<(?:pattern)>
-This groups things like "()" but doesn't make backrefences like "()" does. So
+This is for clustering, not capturing; it groups subexpressions like
+"()", but doesn't make backreferences as "()" does. So
- split(/\b(?:a|b|c)\b/)
+ @fields = split(/\b(?:a|b|c)\b/)
is like
- split(/\b(a|b|c)\b/)
+ @fields = split(/\b(a|b|c)\b/)
but doesn't spit out extra fields.
-=item (?=regexp)
+=item C<(?=pattern)>
A zero-width positive lookahead assertion. For example, C</\w+(?=\t)/>
matches a word followed by a tab, without including the tab in C<$&>.
-=item (?!regexp)
+=item C<(?!pattern)>
A zero-width negative lookahead assertion. For example C</foo(?!bar)/>
matches any occurrence of "foo" that isn't followed by "bar". Note
however that lookahead and lookbehind are NOT the same thing. You cannot
-use this for lookbehind: C</(?!foo)bar/> will not find an occurrence of
-"bar" that is preceded by something which is not "foo". That's because
-the C<(?!foo)> is just saying that the next thing cannot be "foo"--and
-it's not, it's a "bar", so "foobar" will match. You would have to do
-something like C</(?foo)...bar/> for that. We say "like" because there's
-the case of your "bar" not having three characters before it. You could
-cover that this way: C</(?:(?!foo)...|^..?)bar/>. Sometimes it's still
-easier just to say:
-
- if (/foo/ && $` =~ /bar$/)
-
-
-=item (?imsx)
+use this for lookbehind.
+
+If you are looking for a "bar" that isn't preceded by a "foo", C</(?!foo)bar/>
+will not do what you want. That's because the C<(?!foo)> is just saying that
+the next thing cannot be "foo"--and it's not, it's a "bar", so "foobar" will
+match. You would have to do something like C</(?!foo)...bar/> for that. We
+say "like" because there's the case of your "bar" not having three characters
+before it. You could cover that this way: C</(?:(?!foo)...|^.{0,2})bar/>.
+Sometimes it's still easier just to say:
+
+ if (/bar/ && $` !~ /foo$/)
+
+For lookbehind see below.
+
+=item C<(?E<lt>=pattern)>
+
+A zero-width positive lookbehind assertion. For example, C</(?E<lt>=\t)\w+/>
+matches a word following a tab, without including the tab in C<$&>.
+Works only for fixed-width lookbehind.
+
+=item C<(?<!pattern)>
+
+A zero-width negative lookbehind assertion. For example C</(?<!bar)foo/>
+matches any occurrence of "foo" that isn't following "bar".
+Works only for fixed-width lookbehind.
+
+=item C<(?{ code })>
+
+Experimental "evaluate any Perl code" zero-width assertion. Always
+succeeds. C<code> is not interpolated. Currently the rules to
+determine where the C<code> ends are somewhat convoluted.
+
+The C<code> is properly scoped in the following sense: if the assertion
+is backtracked (compare L<"Backtracking">), all the changes introduced after
+C<local>isation are undone, so
+
+ $_ = 'a' x 8;
+ m<
+ (?{ $cnt = 0 }) # Initialize $cnt.
+ (
+ a
+ (?{
+ local $cnt = $cnt + 1; # Update $cnt, backtracking-safe.
+ })
+ )*
+ aaaa
+ (?{ $res = $cnt }) # On success copy to non-localized
+ # location.
+ >x;
+
+will set C<$res = 4>. Note that after the match $cnt returns to the globally
+introduced value 0, since the scopes which restrict C<local> statements
+are unwound.
+
+This assertion may be used as L<C<(?(condition)yes-pattern|no-pattern)>>
+switch. If I<not> used in this way, the result of evaluation of C<code>
+is put into variable $^R. This happens immediately, so $^R can be used from
+other C<(?{ code })> assertions inside the same regular expression.
+
+The above assignment to $^R is properly localized, thus the old value of $^R
+is restored if the assertion is backtracked (compare L<"Backtracking">).
+
+B<WARNING>: This is a grave security risk for arbitrarily interpolated
+patterns. It introduces security holes in previously safe programs.
+A fix to Perl, and to this documentation, will be forthcoming prior
+to the actual 5.005 release.
+
+=item C<(?E<gt>pattern)>
+
+An "independent" subexpression. Matches the substring that a
+I<standalone> C<pattern> would match if anchored at the given position,
+B<and only this substring>.
+
+Say, C<^(?E<gt>a*)ab> will never match, since C<(?E<gt>a*)> (anchored
+at the beginning of string, as above) will match I<all> characters
+C<a> at the beginning of string, leaving no C<a> for C<ab> to match.
+In contrast, C<a*ab> will match the same as C<a+b>, since the match of
+the subgroup C<a*> is influenced by the following group C<ab> (see
+L<"Backtracking">). In particular, C<a*> inside C<a*ab> will match
+less characters that a standalone C<a*>, since this makes the tail match.
+
+An effect similar to C<(?E<gt>pattern)> may be achieved by
+
+ (?=(pattern))\1
+
+since the lookahead is in I<"logical"> context, thus matches the same
+substring as a standalone C<a+>. The following C<\1> eats the matched
+string, thus making a zero-length assertion into an analogue of
+C<(?>...)>. (The difference between these two constructs is that the
+second one uses a catching group, thus shifting ordinals of
+backreferences in the rest of a regular expression.)
+
+This construct is useful for optimizations of "eternal"
+matches, because it will not backtrack (see L<"Backtracking">).
+
+ m{ \( (
+ [^()]+
+ |
+ \( [^()]* \)
+ )+
+ \)
+ }x
+
+That will efficiently match a nonempty group with matching
+two-or-less-level-deep parentheses. However, if there is no such group,
+it will take virtually forever on a long string. That's because there are
+so many different ways to split a long string into several substrings.
+This is essentially what C<(.+)+> is doing, and this is a subpattern
+of the above pattern. Consider that C<((()aaaaaaaaaaaaaaaaaa> on the
+pattern above detects no-match in several seconds, but that each extra
+letter doubles this time. This exponential performance will make it
+appear that your program has hung.
+
+However, a tiny modification of this pattern
+
+ m{ \( (
+ (?> [^()]+ )
+ |
+ \( [^()]* \)
+ )+
+ \)
+ }x
+
+which uses C<(?E<gt>...)> matches exactly when the one above does (verifying
+this yourself would be a productive exercise), but finishes in a fourth
+the time when used on a similar string with 1000000 C<a>s. Be aware,
+however, that this pattern currently triggers a warning message under
+B<-w> saying it C<"matches the null string many times">):
+
+On simple groups, such as the pattern C<(?> [^()]+ )>, a comparable
+effect may be achieved by negative lookahead, as in C<[^()]+ (?! [^()] )>.
+This was only 4 times slower on a string with 1000000 C<a>s.
+
+=item C<(?(condition)yes-pattern|no-pattern)>
+
+=item C<(?(condition)yes-pattern)>
+
+Conditional expression. C<(condition)> should be either an integer in
+parentheses (which is valid if the corresponding pair of parentheses
+matched), or lookahead/lookbehind/evaluate zero-width assertion.
+
+Say,
+
+ m{ ( \( )?
+ [^()]+
+ (?(1) \) )
+ }x
+
+matches a chunk of non-parentheses, possibly included in parentheses
+themselves.
+
+=item C<(?imsx)>
One or more embedded pattern-match modifiers. This is particularly
useful for patterns that are specified in a table somewhere, some of
which want to be case sensitive, and some of which don't. The case
-insensitive ones merely need to include C<(?i)> at the front of the
+insensitive ones need to include merely C<(?i)> at the front of the
pattern. For example:
$pattern = "foobar";
- if ( /$pattern/i )
+ if ( /$pattern/i ) { }
# more flexible:
$pattern = "(?i)foobar";
- if ( /$pattern/ )
+ if ( /$pattern/ ) { }
+
+These modifiers are localized inside an enclosing group (if any). Say,
+
+ ( (?i) blah ) \s+ \1
+
+(assuming C<x> modifier, and no C<i> modifier outside of this group)
+will match a repeated (I<including the case>!) word C<blah> in any
+case.
=back
-The specific choice of question mark for this and the new minimal
-matching construct was because 1) question mark is pretty rare in older
-regular expressions, and 2) whenever you see one, you should stop
-and "question" exactly what is going on. That's psychology...
+A question mark was chosen for this and for the new minimal-matching
+construct because 1) question mark is pretty rare in older regular
+expressions, and 2) whenever you see one, you should stop and "question"
+exactly what is going on. That's psychology...
=head2 Backtracking
-A fundamental feature of regular expression matching involves the notion
-called I<backtracking>. which is used (when needed) by all regular
-expression quantifiers, namely C<*>, C<*?>, C<+>, C<+?>, C<{n,m}>, and
-C<{n,m}?>.
+A fundamental feature of regular expression matching involves the
+notion called I<backtracking>, which is currently used (when needed)
+by all regular expression quantifiers, namely C<*>, C<*?>, C<+>,
+C<+?>, C<{n,m}>, and C<{n,m}?>.
For a regular expression to match, the I<entire> regular expression must
match, not just part of it. So if the beginning of a pattern containing a
finds a possible match right at the beginning of the string, and loads up
$1 with "Foo". However, as soon as the matching engine sees that there's
no whitespace following the "Foo" that it had saved in $1, it realizes its
-mistake and starts over again one character after where it had had the
+mistake and starts over again one character after where it had the
tentative match. This time it goes all the way until the next occurrence
of "foo". The complete regular expression matches this time, and you get
the expected output of "table follows foo."
whole string. As C<\d*> can match on an empty string the complete
regular expression matched successfully.
- Beginning is <I have 2: 53147>, number is <>.
+ Beginning is <I have 2 numbers: 53147>, number is <>.
Here are some variants, most of which don't work:
regular expression is merely a set of assertions that gives a definition
of success. There may be 0, 1, or several different ways that the
definition might succeed against a particular string. And if there are
-multiple ways it might succeed, you need to understand backtracking in
-order to know which variety of success you will achieve.
+multiple ways it might succeed, you need to understand backtracking to
+know which variety of success you will achieve.
When using lookahead assertions and negations, this can all get even
-tricker. Imagine you'd like to find a sequence of nondigits not
+tricker. Imagine you'd like to find a sequence of non-digits not
followed by "123". You might try to write that as
$_ = "ABC123";
3: got AB
4: got ABC
-You might have expected test 3 to fail because it just seems to a more
+You might have expected test 3 to fail because it seems to a more
general purpose version of test 1. The important difference between
them is that test 3 contains a quantifier (C<\D*>) and so can use
backtracking, whereas test 1 will not. What's happening is
that you've asked "Is it true that at the start of $x, following 0 or more
-nondigits, you have something that's not 123?" If the pattern matcher had
+non-digits, you have something that's not 123?" If the pattern matcher had
let C<\D*> expand to "ABC", this would have caused the whole pattern to
-fail.
+fail.
The search engine will initially match C<\D*> with "ABC". Then it will
-try to match C<(?!123> with "123" which, of course, fails. But because
+try to match C<(?!123> with "123", which of course fails. But because
a quantifier (C<\D*>) has been used in the regular expression, the
search engine can backtrack and retry the match differently
-in the hope of matching the complete regular expression.
+in the hope of matching the complete regular expression.
-Well now,
-the pattern really, I<really> wants to succeed, so it uses the
-standard regexp backoff-and-retry and lets C<\D*> expand to just "AB" this
+The pattern really, I<really> wants to succeed, so it uses the
+standard pattern back-off-and-retry and lets C<\D*> expand to just "AB" this
time. Now there's indeed something following "AB" that is not
"123". It's in fact "C123", which suffices.
6: got ABC
-In other words, the two zero-width assertions next to each other work like
+In other words, the two zero-width assertions next to each other work as though
they're ANDed together, just as you'd use any builtin assertions: C</^$/>
matches only if you're at the beginning of the line AND the end of the
line simultaneously. The deeper underlying truth is that juxtaposition in
And if you used C<*>'s instead of limiting it to 0 through 5 matches, then
it would take literally forever--or until you ran out of stack space.
+A powerful tool for optimizing such beasts is "independent" groups,
+which do not backtrace (see L<C<(?E<gt>pattern)>>). Note also that
+zero-length lookahead/lookbehind assertions will not backtrace to make
+the tail match, since they are in "logical" context: only the fact
+whether they match or not is considered relevant. For an example
+where side-effects of a lookahead I<might> have influenced the
+following match, see L<C<(?E<gt>pattern)>>.
+
=head2 Version 8 Regular Expressions
-In case you're not familiar with the "regular" Version 8 regexp
+In case you're not familiar with the "regular" Version 8 regex
routines, here are the pattern-matching rules not described above.
Any single character matches itself, unless it is a I<metacharacter>
with a special meaning described here or above. You can cause
-characters which normally function as metacharacters to be interpreted
-literally by prefixing them with a "\" (e.g. "\." matches a ".", not any
+characters that normally function as metacharacters to be interpreted
+literally by prefixing them with a "\" (e.g., "\." matches a ".", not any
character; "\\" matches a "\"). A series of characters matches that
series of characters in the target string, so the pattern C<blurfl>
would match "blurfl" in the target string.
You can specify a character class, by enclosing a list of characters
-in C<[]>, which will match any one of the characters in the list. If the
+in C<[]>, which will match any one character from the list. If the
first character after the "[" is "^", the class matches any character not
in the list. Within a list, the "-" character is used to specify a
-range, so that C<a-z> represents all the characters between "a" and "z",
-inclusive.
+range, so that C<a-z> represents all characters between "a" and "z",
+inclusive. If you want "-" itself to be a member of a class, put it
+at the start or end of the list, or escape it with a backslash. (The
+following all specify the same class of three characters: C<[-az]>,
+C<[az-]>, and C<[a\-z]>. All are different from C<[a-z]>, which
+specifies a class containing twenty-six characters.)
Characters may be specified using a metacharacter syntax much like that
used in C: "\n" matches a newline, "\t" a tab, "\r" a carriage return,
"\f" a form feed, etc. More generally, \I<nnn>, where I<nnn> is a string
of octal digits, matches the character whose ASCII value is I<nnn>.
-Similarly, \xI<nn>, where I<nn> are hexidecimal digits, matches the
+Similarly, \xI<nn>, where I<nn> are hexadecimal digits, matches the
character whose ASCII value is I<nn>. The expression \cI<x> matches the
ASCII character control-I<x>. Finally, the "." metacharacter matches any
character except "\n" (unless you use C</s>).
You can specify a series of alternatives for a pattern using "|" to
separate them, so that C<fee|fie|foe> will match any of "fee", "fie",
-or "foe" in the target string (as would C<f(e|i|o)e>). Note that the
+or "foe" in the target string (as would C<f(e|i|o)e>). The
first alternative includes everything from the last pattern delimiter
("(", "[", or the beginning of the pattern) up to the first "|", and
the last alternative contains everything from the last "|" to the next
pattern delimiter. For this reason, it's common practice to include
alternatives in parentheses, to minimize confusion about where they
-start and end. Note however that "|" is interpreted as a literal with
-square brackets, so if you write C<[fee|fie|foe]> you're really only
-matching C<[feio|]>.
+start and end.
+
+Alternatives are tried from left to right, so the first
+alternative found for which the entire expression matches, is the one that
+is chosen. This means that alternatives are not necessarily greedy. For
+example: when mathing C<foo|foot> against "barefoot", only the "foo"
+part will match, as that is the first alternative tried, and it successfully
+matches the target string. (This might not seem important, but it is
+important when you are capturing matched text using parentheses.)
+
+Also remember that "|" is interpreted as a literal within square brackets,
+so if you write C<[fee|fie|foe]> you're really only matching C<[feio|]>.
Within a pattern, you may designate subpatterns for later reference by
enclosing them in parentheses, and you may refer back to the I<n>th
subpattern later in the pattern using the metacharacter \I<n>.
Subpatterns are numbered based on the left to right order of their
-opening parenthesis. Note that a backreference matches whatever
+opening parenthesis. A backreference matches whatever
actually matched the subpattern in the string being examined, not the
rules for that subpattern. Therefore, C<(0|0x)\d*\s\1\d*> will
-match "0x1234 0x4321",but not "0x1234 01234", since subpattern 1
+match "0x1234 0x4321", but not "0x1234 01234", because subpattern 1
actually matched "0x", even though the rule C<0|0x> could
potentially match the leading 0 in the second number.
=head2 WARNING on \1 vs $1
-Some people get too used to writing things like
+Some people get too used to writing things like:
$pattern =~ s/(\W)/\\\1/g;
This is grandfathered for the RHS of a substitute to avoid shocking the
B<sed> addicts, but it's a dirty habit to get into. That's because in
-PerlThink, the right-hand side of a C<s///> is a double-quoted string. C<\1> in
+PerlThink, the righthand side of a C<s///> is a double-quoted string. C<\1> in
the usual double-quoted string means a control-A. The customary Unix
meaning of C<\1> is kludged in for C<s///>. However, if you get into the habit
of doing that, you get yourself into trouble if you then add an C</e>
modifier.
- s/(\d+)/ \1 + 1 /eg;
+ s/(\d+)/ \1 + 1 /eg; # causes warning under -w
Or if you try to do
C<${1}000>. Basically, the operation of interpolation should not be confused
with the operation of matching a backreference. Certainly they mean two
different things on the I<left> side of the C<s///>.
+
+=head2 SEE ALSO
+
+L<perlop/"Regexp Quote-Like Operators">.
+
+L<perlfunc/pos>.
+
+L<perllocale>.
+
+I<Mastering Regular Expressions> (see L<perlbook>) by Jeffrey Friedl.
projects / p5sagit/p5-mst-13.2.git / blobdiff