If C<use locale> is in effect, the case map is taken from the current
locale. See L<perllocale>.
-=item m
+=item m
Treat string as multiple lines. That is, change "^" and "$" from matching
at only the very start or end of the string to the start or end of any
line anywhere within the string,
-=item s
+=item s
Treat string as single line. That is, change "." to match any character
whatsoever, even a newline, which it normally would not match.
-=item x
+=item x
Extend your pattern's legibility by permitting whitespace and comments.
the regular expression parser to ignore whitespace that is neither
backslashed nor within a character class. You can use this to break up
your regular expression into (slightly) more readable parts. The C<#>
-character is also treated as a meta-character introducing a comment,
+character is also treated as a metacharacter introducing a comment,
just as in ordinary Perl code. This also means that if you want real
whitespace or C<#> characters in the pattern that you'll have to either
escape them or encode them using octal or hex escapes. Taken together,
In particular the following metacharacters have their standard I<egrep>-ish
meanings:
- \ Quote the next meta-character
+ \ Quote the next metacharacter
^ Match the beginning of the line
. Match any character (except newline)
$ Match the end of the line (or before newline at the end)
modifier to C<{1,}>, and the "?" modifier to C<{0,1}>. n and m are limited
to integral values less than 65536.
-By default, a quantified sub-pattern is "greedy", that is, it will match as
-many times as possible while still allowing the rest of the pattern to match.
-If you want to match the minimum number of times possible, follow the
-quantifier with a "?". Note that the meanings don't change, just the
-"gravity":
+By default, a quantified subpattern is "greedy", that is, it will match as
+many times as possible (given a particular starting location) while still
+allowing the rest of the pattern to match. If you want it to match the
+minimum number of times possible, follow the quantifier with a "?". Note
+that the meanings don't change, just the "greediness":
*? Match 0 or more times
+? Match 1 or more times
\B Match a non-(word boundary)
\A Match at only beginning of string
\Z Match at only end of string (or before newline at the end)
- \G Match only where previous m//g left off
+ \G Match only where previous m//g left off (works only with /g)
A word boundary (C<\b>) is defined as a spot between two characters that
has a C<\w> on one side of it and a C<\W> on the other side of it (in
just like "^" and "$" except that they won't match multiple times when the
C</m> modifier is used, while "^" and "$" will match at every internal line
boundary. To match the actual end of the string, not ignoring newline,
-you can use C<\Z(?!\n)>. The C<\G> assertion can be used to mix global
-matches (using C<m//g>) and non-global ones, as described in
+you can use C<\Z(?!\n)>. The C<\G> assertion can be used to chain global
+matches (using C<m//g>), as described in
L<perlop/"Regexp Quote-Like Operators">.
+
It is also useful when writing C<lex>-like scanners, when you have several
regexps which you want to match against consequent substrings of your
string, see the previous reference.
alphanumeric, such as C<\b>, C<\w>, C<\n>. Unlike some other regular expression
languages, there are no backslashed symbols that aren't alphanumeric.
So anything that looks like \\, \(, \), \E<lt>, \E<gt>, \{, or \} is always
-interpreted as a literal character, not a meta-character. This makes it
+interpreted as a literal character, not a metacharacter. This makes it
simple to quote a string that you want to use for a pattern but that
you are afraid might contain metacharacters. Quote simply all the
non-alphanumeric characters:
$pattern =~ s/(\W)/\\$1/g;
-You can also use the built-in quotemeta() function to do this.
+You can also use the builtin quotemeta() function to do this.
An even easier way to quote metacharacters right in the match operator
is to say
multiple ways it might succeed, you need to understand backtracking to know which variety of success you will achieve.
When using lookahead assertions and negations, this can all get even
-tricker. Imagine you'd like to find a sequence of non-digits not
+tricker. Imagine you'd like to find a sequence of non-digits not
followed by "123". You might try to write that as
$_ = "ABC123";
that you've asked "Is it true that at the start of $x, following 0 or more
non-digits, you have something that's not 123?" If the pattern matcher had
let C<\D*> expand to "ABC", this would have caused the whole pattern to
-fail.
+fail.
The search engine will initially match C<\D*> with "ABC". Then it will
try to match C<(?!123> with "123" which, of course, fails. But because
a quantifier (C<\D*>) has been used in the regular expression, the
search engine can backtrack and retry the match differently
-in the hope of matching the complete regular expression.
+in the hope of matching the complete regular expression.
-Well now,
+Well now,
the pattern really, I<really> wants to succeed, so it uses the
standard regexp back-off-and-retry and lets C<\D*> expand to just "AB" this
time. Now there's indeed something following "AB" that is not
In case you're not familiar with the "regular" Version 8 regexp
routines, here are the pattern-matching rules not described above.
-Any single character matches itself, unless it is a I<meta-character>
+Any single character matches itself, unless it is a I<metacharacter>
with a special meaning described here or above. You can cause
characters which normally function as metacharacters to be interpreted
literally by prefixing them with a "\" (e.g., "\." matches a ".", not any
range, so that C<a-z> represents all the characters between "a" and "z",
inclusive.
-Characters may be specified using a meta-character syntax much like that
+Characters may be specified using a metacharacter syntax much like that
used in C: "\n" matches a newline, "\t" a tab, "\r" a carriage return,
"\f" a form feed, etc. More generally, \I<nnn>, where I<nnn> is a string
of octal digits, matches the character whose ASCII value is I<nnn>.
Similarly, \xI<nn>, where I<nn> are hexadecimal digits, matches the
character whose ASCII value is I<nn>. The expression \cI<x> matches the
-ASCII character control-I<x>. Finally, the "." meta-character matches any
+ASCII character control-I<x>. Finally, the "." metacharacter matches any
character except "\n" (unless you use C</s>).
You can specify a series of alternatives for a pattern using "|" to
square brackets, so if you write C<[fee|fie|foe]> you're really only
matching C<[feio|]>.
-Within a pattern, you may designate sub-patterns for later reference by
+Within a pattern, you may designate subpatterns for later reference by
enclosing them in parentheses, and you may refer back to the I<n>th
-sub-pattern later in the pattern using the meta-character \I<n>.
-Sub-patterns are numbered based on the left to right order of their
+subpattern later in the pattern using the metacharacter \I<n>.
+Subpatterns are numbered based on the left to right order of their
opening parenthesis. Note that a backreference matches whatever
-actually matched the sub-pattern in the string being examined, not the
-rules for that sub-pattern. Therefore, C<(0|0x)\d*\s\1\d*> will
-match "0x1234 0x4321",but not "0x1234 01234", because sub-pattern 1
+actually matched the subpattern in the string being examined, not the
+rules for that subpattern. Therefore, C<(0|0x)\d*\s\1\d*> will
+match "0x1234 0x4321",but not "0x1234 01234", because subpattern 1
actually matched "0x", even though the rule C<0|0x> could
potentially match the leading 0 in the second number.
C<${1}000>. Basically, the operation of interpolation should not be confused
with the operation of matching a backreference. Certainly they mean two
different things on the I<left> side of the C<s///>.
+
+=head2 SEE ALSO
+
+"Mastering Regular Expressions" (see L<perlbook>) by Jeffrey Friedl.
projects / p5sagit/p5-mst-13.2.git / blobdiff