the standard input. If you open minus for writing, it really means to
access the standard output.
-If minus can be used as the default input or default output? What happens
+If minus can be used as the default input or default output, what happens
if you open a pipe into or out of minus? What's the default command it
-would run? The same script as you're current running! This is actually
+would run? The same script as you're currently running! This is actually
a stealth C<fork> hidden inside an C<open> call. See L<perlipc/"Safe Pipe
Opens"> for details.