print $i++; # prints 0
print ++$j; # prints 1
+Note that just as in C, Perl doesn't define B<when> the variable is
+incremented or decremented. You just know it will be done sometime
+before or after the value is returned. This also means that modifying
+a variable twice in the same statement will lead to undefined behaviour.
+Avoid statements like:
+
+ $i = $i ++;
+ print ++ $i + $i ++;
+
+Perl will not guarantee what the result of the above statements is.
+
The auto-increment operator has a little extra builtin magic to it. If
you increment a variable that is numeric, or that has ever been used in
a numeric context, you get a normal increment. If, however, the
the operand is an identifier, a string consisting of a minus sign
concatenated with the identifier is returned. Otherwise, if the string
starts with a plus or minus, a string starting with the opposite sign
-is returned. One effect of these rules is that C<-bareword> is equivalent
-to C<"-bareword">.
+is returned. One effect of these rules is that -bareword is equivalent
+to "-bareword".
Unary "~" performs bitwise negation, i.e., 1's complement. For
example, C<0666 & ~027> is 0640. (See also L<Integer Arithmetic> and
supposed to be searched, substituted, or transliterated instead of the default
$_. When used in scalar context, the return value generally indicates the
success of the operation. Behavior in list context depends on the particular
-operator. See L</"Regexp Quote-Like Operators"> for details.
+operator. See L</"Regexp Quote-Like Operators"> for details and
+L<perlretut> for examples using these operators.
If the right argument is an expression rather than a search pattern,
substitution, or transliteration, it is interpreted as a search pattern at run
operand is not enclosed in parentheses, it returns a string consisting
of the left operand repeated the number of times specified by the right
operand. In list context, if the left operand is enclosed in
-parentheses, it repeats the list.
+parentheses, it repeats the list. If the right operand is zero or
+negative, it returns an empty string or an empty list, depending on the
+context.
print '-' x 80; # print row of dashes
close ARGV if eof; # reset $. each file
}
-As a list operator:
+Here's a simple example to illustrate the difference between
+the two range operators:
+
+ @lines = (" - Foo",
+ "01 - Bar",
+ "1 - Baz",
+ " - Quux");
+
+ foreach(@lines)
+ {
+ if (/0/ .. /1/)
+ {
+ print "$_\n";
+ }
+ }
+
+This program will print only the line containing "Bar". If
+the range operator is changed to C<...>, it will also print the
+"Baz" line.
+
+And now some examples as a list operator:
for (101 .. 200) { print; } # print $_ 100 times
@foo = @foo[0 .. $#foo]; # an expensive no-op
\c[ control char (ESC)
\N{name} named Unicode character
+B<NOTE>: Unlike C and other languages, Perl has no \v escape sequence for
+the vertical tab (VT - ASCII 11).
+
The following escape sequences are available in constructs that interpolate
but not in transliterations.
$output = `cmd 3>&1 1>&2 2>&3 3>&-`;
To read both a command's STDOUT and its STDERR separately, it's easiest
-and safest to redirect them separately to files, and then read from those
-files when the program is done:
+to redirect them separately to files, and then read from those files
+when the program is done:
- system("program args 1>/tmp/program.stdout 2>/tmp/program.stderr");
+ system("program args 1>program.stdout 2>program.stderr");
Using single-quote as a delimiter protects the command from Perl's
double-quote interpolation, passing it on to the shell instead:
the compiler will precompute the number which that expression
represents so that the interpreter won't have to.
+=head2 No-ops
+
+Perl doesn't officially have a no-op operator, but the bare constants
+C<0> and C<1> are special-cased to not produce a warning in a void
+context, so you can for example safely do
+
+ 1 while foo();
+
=head2 Bitwise String Operators
Bitstrings of any size may be manipulated by the bitwise operators
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