Calling a subroutine as C<&foo> with no trailing parentheses ignores
the prototype of C<foo> and passes it the current value of the argument
list, C<@_>. Here's an example; the C<bar> subroutine calls C<&foo>,
-which prints its argument list:
+which prints what its arguments list:
sub bar { &foo }
your PATH, which might also mean that the location of perl is not
where you expect it so you need to adjust your shebang line.
-=head1 REVISION
-
-Revision: $Revision$
-
-Date: $Date$
-
-See L<perlfaq> for source control details and availability.
-
=head1 AUTHOR AND COPYRIGHT
-Copyright (c) 1997-2009 Tom Christiansen, Nathan Torkington, and
+Copyright (c) 1997-2010 Tom Christiansen, Nathan Torkington, and
other authors as noted. All rights reserved.
This documentation is free; you can redistribute it and/or modify it