:utf8 works only with perlio.

[p5sagit/p5-mst-13.2.git] / pod / perl56delta.pod

diff --git a/pod/perl56delta.pod b/pod/perl56delta.pod
index d11f908..75d7728 100644 (file)
--- a/pod/perl56delta.pod
+++ b/pod/perl56delta.pod
@@ -112,16 +112,14 @@ to check if you're running a particular version of Perl:
         # new features supported
     }
 
-C<require> and C<use> also have some special magic to support such literals.
-They will be interpreted as a version rather than as a module name:
+C<require> and C<use> also have some special magic to support such
+literals, but this particular usage should be avoided because it leads to
+misleading error messages under versions of Perl which don't support vector
+strings.  Using a true version number will ensure correct behavior in all
+versions of Perl:
 
-    require v5.6.0;            # croak if $^V lt v5.6.0
-    use v5.6.0;                        # same, but croaks at compile-time
-
-Alternatively, the C<v> may be omitted if there is more than one dot:
-
-    require 5.6.0;
-    use 5.6.0;
+    require 5.006;    # run time check for v5.6
+    use 5.006_001;    # compile time check for v5.6.1
 
 Also, C<sprintf> and C<printf> support the Perl-specific format flag C<%v>
 to print ordinals of characters in arbitrary strings:
@@ -2631,9 +2629,12 @@ but still allowed it.
 
 In Perl 5.6.0 and later, C<"$$1"> always means C<"${$1}">.
 
-=item delete(), values() and C<\(%h)> operate on aliases to values, not copies
+=item delete(), each(), values() and C<\(%h)>
 
-delete(), each(), values() and hashes in a list context return the actual
+operate on aliases to values, not copies
+
+delete(), each(), values() and hashes (e.g. C<\(%h)>)
+in a list context return the actual
 values in the hash, instead of copies (as they used to in earlier
 versions).  Typical idioms for using these constructs copy the
 returned values, but this can make a significant difference when
@@ -2913,7 +2914,9 @@ include the following:
 
 =item The DB module
 
-=item The regular expression constructs C<(?{ code })> and C<(??{ code })>
+=item The regular expression code constructs: 
+
+C<(?{ code })> and C<(??{ code })>
 
 =back