Fixing \G bug by Francois Desarmenien

[p5sagit/p5-mst-13.2.git] / t / op / groups.t

#!./perl

$ENV{PATH} ="/bin:/usr/bin:/usr/xpg4/bin:/usr/ucb" .
    exists $ENV{PATH} ? ":$ENV{PATH}" : "";
$ENV{LC_ALL} = "C"; # so that external utilities speak English
$ENV{LANGUAGE} = 'C'; # GNU locale extension

sub quit {
    print "1..0\n";
    exit 0;
}

quit() if $^O eq 'MSWin32';

# We have to find a command that prints all (effective
# and real) group names (not ids).  The known commands are:
# groups
# id -Gn
# id -a
# Beware 1: some systems do just 'id -G' even when 'id -Gn' is used.
# Beware 2: id -Gn or id -a format might be id(name) or name(id).
# Beware 3: the groups= might be anywhere in the id output.
# Beware 4: groups can have spaces ('id -a' being the only defense against this)
# Beware 5: id -a might not contain the groups= part.
#
# That is, we might meet the following:
#
# foo bar zot				# accept
# foo 22 42 bar zot			# accept
# 1 22 42 2 3				# reject
# groups=(42),foo(1),bar(2),zot me(3)	# parse
# groups=22,42,1(foo),2(bar),3(zot me)	# parse
#
# and the groups= might be after, before, or between uid=... and gid=...

GROUPS: {
    # prefer 'id' over 'groups' (is this ever wrong anywhere?)
    # and 'id -a' over 'id -Gn' (the former is good about spaces in group names)
    if (($groups = `id -a 2>/dev/null`) ne '') {
	# $groups is of the form:
	# uid=39957(gsar) gid=22(users) groups=33536,39181,22(users),0(root),1067(dev)
	last GROUPS if $groups =~ /groups=/;
    }
    if (($groups = `id -Gn 2>/dev/null`) ne '') {
	# $groups could be of the form:
	# users 33536 39181 root dev
	last GROUPS if $groups !~ /^(\d|\s)+$/;
    }
    if (($groups = `groups 2>/dev/null`) ne '') {
	# may not reflect all groups in some places, so do a sanity check
	if (-d '/afs') {
	    print <<EOM;
# These test results *may* be bogus, as you appear to have AFS,
# and I can't find a working 'id' in your PATH (which I have set
# to '$ENV{PATH}').
#
# If these tests fail, report the particular incantation you use
# on this platform to find *all* the groups that an arbitrary
# luser may belong to, using the 'perlbug' program.
EOM
	}
	last GROUPS;
    }
    # Okay, not today.
    quit();
}

# Remember that group names can contain whitespace, '-', et cetera.
# That is: do not \w, do not \S.
if ($groups =~ /groups=(.+)( [ug]id=|$)/) {
    my $gr = $1;
    my @g0 = split /,/, $gr;
    my @g1;
    # prefer names over numbers
    for (@g0) {
        # 42(zot me)
	if (/^(\d+)(?:\(([^)]+)\))?$/) {
	    push @g1, ($2 || $1);
	}
        # zot me(42)
	elsif (/^([^(]*)\((\d+)\)$/) {
	    push @g1, ($1 || $2);
	}
	else {
	    print "# ignoring group entry [$_]\n";
	}
    }
    print "# groups=$gr\n";
    print "# g0 = @g0\n";
    print "# g1 = @g1\n";
    $groups = "@g1";
}

print "1..2\n";

$pwgid = $( + 0;
($pwgnam) = getgrgid($pwgid);
@basegroup{$pwgid,$pwgnam} = (1,1);

$seen{$pwgid}++;

for (split(' ', $()) {
    next if $seen{$_}++;
    ($group) = getgrgid($_);
    if (defined $group) {
	push(@gr, $group);
    }
    else {
	push(@gr, $_);
    }
} 

if ($^O eq "uwin") { # Or anybody else who can have spaces in group names.
	$gr1 = join(' ', grep(!$did{$_}++, sort split(' ', join(' ', @gr))));
} else {
	$gr1 = join(' ', sort @gr);
}

$gr2 = join(' ', grep(!$basegroup{$_}++, sort split(' ',$groups)));

if ($gr1 eq $gr2) {
    print "ok 1\n";
}
else {
    print "#gr1 is <$gr1>\n";
    print "#gr2 is <$gr2>\n";
    print "not ok 1\n";
}

# multiple 0's indicate GROUPSTYPE is currently long but should be short

if ($pwgid == 0 || $seen{0} < 2) {
    print "ok 2\n";
}
else {
    print "not ok 2 (groupstype should be type short, not long)\n";
}